Open folder path in Finder

[mbuchetics]

Let's say I open Alfred and enter a path like "~/Library/LaunchAgents". Alfred will now show me the contents of this path, but what I want are file actions for THIS path, mainly to open it in the Finder. If I enter "~/Library/" instead, it shows me the "LaunchAgents" subfolder and I can choose "Reveal in Finder".

Is there a way to directly execute file/folder actions on the typed path?

 

[mbuchetics]

Ok, I am stupid. "Cmd + Return" does exactly what I wanted and opens the folder in the finder.

But is there a way to access the other actions?

[Ddyracer]

Ok, I am stupid. "Cmd + Return" does exactly what I wanted and opens the folder in the finder.

But is there a way to access the other actions?

What do you mean? File actions?

[jdfwarrior]

Ok, I am stupid. "Cmd + Return" does exactly what I wanted and opens the folder in the finder.

But is there a way to access the other actions?

 

When you paste in a path into Alfred, it appends a / which makes it show the contents of that path. You could press backspace.. that would remove the LaunchAgents/ portion from the path but leave it highlighted. Then you could press the right arrow to get to the actions.

 

Not sure where you are getting the path from but, if you simply highlight the path somewhere (terminal for example) and press the action hotkey (cmd+opt+\) it will open directly to result actions for that selected path. This action also works with folders and files selected in Finder.